Chicken food riddle
Farmer John has a chicken farm. On a certain day, John calculates in how many days he will run out of chicken-food. He notices that if he would sell 75 of his chickens, he could feed the remaining chickens twenty days longer with the chicken-food he has, and that if he would buy 100 extra chickens, he would run out of chicken-food fifteen days earlier.
How many chickens does farmer John have?
Some explanation on the answer Yodha already gave.
The product of the number of chickens and the number of days stays the same, which leads to the following calculations:
C*D = (C-75)*(D+20) = (C+100)*(D-15)
C*D = C*D+20C-75D-1500 = C*D-15C+100D-1500
0 = 20C-75D-1500 = -15C+100D-1500
60C = 225D+4500
60C = 400D-6000
225D+4500 = 400D-6000
175D = 10500
D = 10500/175 = 60
C = 225 + 75
= 400 – 100
= 300
could have upvote my answer xd
Your Answer
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