Separate number in groups puzzle
You need to divide numbers from 1 to 9 into two group such that sum of numbers in one group is equal to the sum of other group.
Note(Very Carefully) : 6 cannot be flipped over to make it 9.
6 cannot be flipped over to make it 9…but 9 can be flipped to over to make 6
sol-(6+7+2=15) and (8+4+3=15)
where is the numbers 1,5,6??
ANSWER- 1 2 3 4 5 9(rotated 6) and 7 8 9
EXPLANATION-
Sum of numbers 1 2 3 4 5 6 7 8 9 is 45 ,
So, numbers cant be split into 2 equal parts.
Given that, we cant turn 9 upside down and make it 6
but we can turn 6 to make it 9
So,
1+2+3+4+5+9(Rotated 6) =24
7+8+9 = 24
So, the two group of numbers are 1,2,3,4,5,6 and 7,8,9
Wrong answer: it was clearly said that: 6 cannot be flipped over to make it 9!!
Sum of numbers 1-9 is 45 so it can’t be slitted into 2 equal groups. But given that 6 cannot be flipped over to make it 9 does not mean the opposite is also true, so if we flip the 9 to be 6 the sum is 42 which can be split to 21 for each group.
So the groups are 1+2+3+4+5+6=21 and 6+7+8=21
Your Answer
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