# THE BOY OR GIRL PARADOX

Imagine that a family has two children, one of whom we know to be a boy. What then is the probability that the other child is a boy? The obvious answer is to say that the probability is 1/2—after all, the other child can only be *either* a boy *or* a girl, and the chances of a baby being born a boy or a girl are (essentially) equal. In a two-child family, however, there are actually four possible combinations of children: two boys (MM), two girls (FF), an older boy and a younger girl (MF), and an older girl and a younger boy (FM). We already know that one of the children is a boy, meaning we can eliminate the combination FF, but that leaves us with three equally possible combinations of children in which *at least* one is a boy—namely MM, MF, and FM. This means that the probability that the other child *is* a boy—MM—must be 1/3, not 1/2.

… It’s already solved!

To the moderator/webmaster: You need to create a special category for this one: “Spoiler puzzles”! :))

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