Vampires biting puzzle
A vampire enters a town and bites 2 person every night. The bitten 2 persons grows in to two big vampires and bites 4 persons the next night. These 4 vampires bites 6 people the next night and the 6 bites 8 and so on…….
How many vampires will be there on the 5th night?
Answer-71( assuming the bitten people don’t bite a larger group every next night)
Explanation:
No of people bitten
1st night 2nd night 3rd night 4th night 5th night
The first vampire – 2 2 2 2 2 – 10
The Two new vampires
bite 4 persons
the next night – nil 4 4 4 4 -16
The Four new vampires
bite 6 persons
the next night – nil nil 6 6 6 -18
The Six new vampires
bite 8 persons
the next night – nil nil nil 8 8 -16
The Eight new vampires
bite 10 persons
the next night – nil nil nil nil 10 -10
Total -70
The answer is 71 including the first vampire
No of Vampires in First night 1
No of Persons Bitten in first Night 2
No of Vampires in Second Night 1+2 =3
No of Persons Bitten in Second Night 2+4 =6
No of vampires In Third Night 1+2+2+4 =9
No of Persons bitten in Third Night 2+4+4+6 =16
No of Vampires in Fourth Night 1+2+2+4+2+4+4+6=25
No of Persons bitten in Forth Night 2+4+4+6+4+6+6+8=40
No of Vampires in Fifth Night 1+2+2+4+2+4+4+6+2+4+4+6+4+6+6+8=65
No of persons bitten in Fifth night is 2+4+4+6+4+6+6+8+4+6+6+8+6+8+8+10 = 96
So the Number of Vampires in Fifth Night is 65
Your Answer
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