The Chicken and Leg Problem
This is a typical algebra problem with two unknowns, and we need to have two equations to solve the problem. Let X be the number of cows, and Y the number of chickens.
The number of cows plus the number of chickens equals 30:
X + Y = 30
Since cows have four legs and chickens have two legs, we can also have an equation for the number of legs.
4 X + 2 Y = 74
Rearranging the first equation we get
X = 30 – Y
Substituting X in the second equation gives us
4 × (30 – Y) + 2 Y = 74
120 – 4 Y + 2 Y = 74
-2 Y = 74 – 120 = -46
Y = 23
The farmer has 23 chickens. (and 7 cows).
Your Answer
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