Four rivers and three temples
All the rivers are magical, moment a worshiper crosses a river with any number of flowers, it becomes double. (For eg 1 flower becomes 2 flowers, 2 become 4 and so on).
How many minimum number of flowers a worshiper needs 2 carry from beginning such that he offers equal number of flowers in all the three temples, and he is left with zero flowers at the end of fourth river.
Solve this ??
Starts with x flowers and offers y flowers
Starts with x
Crosses 1st river to get 2x flowers and after offering y has 2x-y
Crosses 2nd river and has 4x-2y flowers and after offering y has 4x-3y
Crosses3rd river and has 8x-6y flowers and after offering y has 8x-7y
So after or before crossing must be zero
8x-7y = 0
8x=7y
x/y=7/8
x=7
y=8
7 flowers to begin and offer 8 flowers
Your Answer
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