Harish596's Profile
Curious
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Harish596 loves solving puzzles at PuzzleFry.com. I am proud PuzzleFry member and like my time invested in solving brain teasers.
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2 = 5 [2^2 + (2^0) ]
3 = 12 [3^2 + (3^1 x 2^0)]
4 = 28 [4^2 + (2^2 x 3^1)]
5 = 133 [5^2 + (3^2 x 2^2)]
For even number
n = n^2 + (2^n-2 x 3^n-3) for all n>2
For odd number
n = n^2 + (3^n-2 x 2^n-3) for all n>1
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