They were bord BC

His daughters are 3, 3, and 8. The prime factorization of 72 is 1 * 2 * 2 * 2 * 3 * 3, so the possible ages are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24 ,36. Using the prime factorization and these numbers the only combinations of numbers that work for the first clue are:
1) 1*1*72        2)  1*2*36                  3)  1*3*24                   4)  1*4*18
5) 1*6*12        6)  1*8*9                     7)  2*2*18                   8)  2*3*12
9) 2*4*9          10) 2*6*6                    11) 3*3*8                    12) 3*4*6

The first options is not reasonable, the 2nd also but we proceed. Since he doesn’t know the ages after this piece of information the sum of the three numbers must not be unique
1)  1+2+36=39            2)  1+3+24=28            3) 1+4+18=23
4) 1+6+12=19            5)  1+8+9=18                6)  2+2+18=22
7)  2+3+12=17          8) 2+4+9=15                  9) 2+6+6=14
10) 3+3+8=14           12) 3+4+6=13

Options 9,10 are the same. So now comes the 3rd clue.: there is an older daughter so it must be 8,3,3

I wonder who is the kid that can solve it. After all 130.8 viewed this this riddle and did not solve it.

Answer:                   5 4 7 8 0 9
+  0 8 7 5 4 9
+  7 8 0 9 5 4
=========
1 4 1 6 3 1 2

The prisoners give themselves numbers from 1 to 100 and determine among themselves what each prisoner should do when he leaves.
Every prisoner whose number is less than 100 turns on the lamp if it is off and on the condition that he has never turned it on yet.
The prisoner whose number is 100 turns off the lamp if it is on and counts the number of times he turned it off.
After counting 99 times, he informs the warden that all prisoners have already gone out into the room at least once.

it took a few tragic events for engineers to take a fresh look at airplane window design. It was in the 1950s when commercial airliners were getting bigger — and they also started disintegrating in midair. Two of those were de Havilland Comets, which fell apart in flight in separate events in 1953 and 1954. The cause was found to be … yup, the square windows.

Engineers determined that the sharp edges of the planes’ squared windows created natural weak spots, causing “metal fatigue failure.” These corners were easily stressed, then further weakened by air pressure at high altitude.

By the ’50s, aircraft like the de Havilland Comets were flying faster and higher than industry predecessors, meaning after multiple flights and repeated pressurization, those square windows basically broke apart from the pressure.

Rounded windows, on the other hand, are able to distribute the pressure evenly because they have no corners for stress to concentrate, reducing the likelihood of cracks or breaks. Circular shapes are also stronger and resist deformation, making them more able to withstand the repeated pressure differences between the inside and outside of the aircraft.

Let X be the number of  2 paise stamps so 6X is the number of 1 paisa stamps. But the amount of money paid for them will be 2*x+6*x =8X so 75-8X must be a number that can be divided by 5 with no remainder. So the only solution is 5 stamps of 2 paise, 30 stamps of 1 paise and 7 stamps of 5 paise

Not necessary!! Because she might also sneeze  when there is no rain coming (in summer for example)

There are only 8 characters so there is more than one solution!!
Since S+S=T and  T+ O = O meaning  T is zero or 10 (9+1) so T can not be zero hence  it has to be 9 therefor S must be 4.
And since we also have R+E=E than R must be zero.
Now M+S < 10 so M+4 < 9 than M can be 1,2,3

If M=1 than L=5 and L+ O > 10 than O can be 7 or 8 so we get

4   9   7   0          1                4   9    8   0         1
+                                               +
4   7   5  3,6,8   4                4  8    5  2,6,7   4
============              ============
9   7   2  3,6,8   5                 9  8   3  2,6,7   5

If M=2 than L=6  and L+0 > 10 than O can be 5 or 7 so we get

4   9   5      0      2                 4   9   7       0      2
+                                                +
4   5   6  3,7,8  4                 4   7   6  1,5,8   4
===========                 ============
9   5  1  3,7,8   6                 9   7   3   1,5,8   6

If M=3 than  L=7  and L+O > 10 than O can be 5 or 8 so we get

4   9   5      0       3              4   9   8       0       3
+                                             +
4   5   7  1,6,8   4              4   8   7  1,2,6    4
===========              ============
9   5   2   1,6,8  7              9   8   5  1,2,6    7

It can not be done.
When we remove 2 squares of the chess board at diagonally opposite corners they have the same color so there is a difference between the blacks and white colors now and  since each carboard is covering 2 squares that are made of black and white we cant cover two whites or two blacks squares

Lets mark the caves with the numbers 1-13 where 13 is near cave 1. One  treasure seeker will start from cave 1 clockwise and the other will start from cave 13 anti-clockwise. and each day they progress to the next cave. Actually they do a pincer movement so there is now way that the treasure keepers can avoid the seekers because they get closer to one side or the other.