# Burning house rescue within time riddle

Group of friends are trapped in a burning house. The house is going to collapse in 12 minutes so they desperately want to get out. They have to run through a hallway which is in flames. If someone wants to pass through he has to have a fire extinguisher to hold the flames back at least a little. Problem is that the friends have only one.

Only two people can go at once. Than somebody has to return with the extinguisher and other two can go.

There is one fireman among the friends who moves through flames with ease and he can ran through the hallway in one minute. His best friend who is in great shape can run through in 2 minutes. There is an older man who needs four minutes and a drunken guy who will need 5 minutes to pass through. If two people go together they move at speed of the slower one.

How will they do it so that they all get out before the house collapses?

Fireman and runner exit house at t = 2min

Fireman runs back into house and meets other two at t = 3min

Ol man and drunk exit burning house at t = 8min

Runner runs into burning house and meets fireman at t = 10min

Runner and fireman exit burning hkuse at t = 12min happily ever after

Best Friend + Fireman (2)

Fireman Returns (1)

Drunken Man + Old Man (5)

Best Friend Returns (2)

Best Friend + Fireman (2)

TOTAL = 12 Minutes

### Your Answer

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