Magical flowers!!

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A  devotee goes to three temples,  temple1, temple2  and temple3  one after the other.
In front of each temple, there is a small pool.  So while going to each temple
he takes some flowers with him and  takes holy bath  in a pool belongs to that temple.
If he takes a bath in one pool the flowers which he had earlier get doubled.

One day the devotee goes to a temple1 with flowers and takes a bath in a pool and the
flowers get doubled. He  keeps some flowers for god and move to  temple2
along  flowers he left with.  Again takes a bath in a pool, flowers get doubled and keeps
the same number of flowers which he has kept in temple1. Again  the same procedure continues in  temple3 where he keeps the flowers which he has kept in temple1 and
temple2 and comes out with  empty hands (no flowers left out).

1. What are the initial number of flowers the devotee had?
2. How many flowers did he keep in each temple?

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  • 2 Answer(s)

    1. What are the initial number of flowers the devotee had?
    SOLUTION 7 flowers

    2. How many flowers did he keep in each temple?
    SOLUTION 8 flowers

    EXPLANATION-
    Let the initial no. of flower be X
    Let No. of flowers devoted at each temple be Y

    Temple 1 – 
    Flower becomes – 2X
    Flowers devoted – Y
    Flowers Left = (2X-Y)

    Temple 2-
    Flower becomes – 2*(2X-Y) = 4X-2Y
    Flowers devoted
     – Y
    Flowers Left = (4X-3Y)

    Temple 3-
    Flower becomes – 2*(4X-3Y)
    Flowers devoted
     – Y
    Flowers Left = (8X-7Y)

    We know at the end no flowers were left
    i.e. 
    8X-7Y=0
    X=7Y/8

    So, Numbers which satisfies above equation is –
    X=7
    Y=8

    Detective Expert Answered on 6th September 2015.

    Nice, Thank you.

    on 6th September 2015.
    Add Comment

    Above answer is right and if ques is like this….

    He returns with same number of flowers as he entered in the Temple 1.

    Then answer will
    Enters with X
    Leaves X flowers

    sainath495 Curious Answered on 16th October 2016.
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