Strategy for a 2 Player Coin Game
Consider a two player coin game where each player gets turn one by one. There is a row of even number of coins, and a player on his/her turn can pick a coin from any of the two corners of the row. The player that collects coins with more value wins the game. Develop a strategy for the player making the first turn, such he/she never looses the game.
Note that the strategy to pick maximum of two corners may not work. In the following example, first player looses the game when he/she uses strategy to pick maximum of two corners.
Example 18 20 15 30 10 14 First Player picks 18, now row of coins is 20 15 30 10 14 Second player picks 20, now row of coins is 15 30 10 14 First Player picks 15, now row of coins is 30 10 14 Second player picks 30, now row of coins is 10 14 First Player picks 14, now row of coins is 10 Second player picks 10, game over. The total value collected by second player is more (20 + 30 + 10) compared to first player (18 + 15 + 14). So the second player wins.
The first player loses iff n=6k+1
If n=1, the first player is forced to take it and hence loses. Now that we have identified a losing position, it makes sense to send the opponent to the losing position. Hence if n=2,3,4,5 or 6, the first player can take away n-1 coins and give just 1 coin to the opponent, forcing them to lose.
If n=7, anything that the first player does, the opponent is going to end up with 2,3,4,5 or 6 coins. But as explained earlier, the opponent can then take away the required number of coins to give a single coin to the first player, forcing them to lose. Thus n=7 is a losing position, from which it follows that n=8,9,10,11 and 12 are winning positions.
By induction, it can be proved that numbers of the form 6k+1 are the losing positions. In general, in an impartial game that is acyclic and guaranteed to end in a win for one player, here is the procedure to find out which states are winning positions for the first player. Suppose that there is a property P that you can assign to some of the game states such that:
- The ultimate losing state satisfies the property P
- From a state that satisfies P, it is impossible to move to another state that satisfies P
- From any state that does not satisfy P, it is possible to move to some state that satisfies P
In such a case, the P states are exactly the losing states.
For this problem, let us define the property P for states (integers for us) as n leaves remainder 1 on division by 6. Then it is easy to see that:
- The ultimate losing state (1) satisfies P
- From a number that is 1 modulo 6, it is impossible to obtain another one by subtracting 1,2,3,4 or 5. That is, We cannot move from a P state to another
- From a number that is 0,2,3,4 or 5 modulo 6, we can subtract 5,1,2,3 and 4 respectively to obtain a number which is 1 modulo 6. That is, from any non-P state, we can move to a P-state
Hence the only losing states are those with integers that are 1 modulo 6.
Player 1 picks the first coin from right end and player 2 picks coin which have higher value from either end in next step player 1 can continue to pick up higher value coin from either end
Your Answer
More puzzles to try-
Game of Kids riddle
It’s always 1 to 6, it’s always 15 to 20, it’s always 5, but it’s never 21, unless it’s flying. ...Read More »Evaluating a polynomial
There is a polynomial and you have access to a function that evaluates that polynomial at a given number. You ...Read More »Men rescued from sea puzzle
A man fell off a smuggling boat into deep water. He could not swim and he was not wearing anything ...Read More »Maximum count puzzle
A fast food restaurant sells chicken in orders of 6, 9, and 20. What is the largest number of pieces ...Read More »Count The Squares
Find the number of squares in the below-given picture.Read More »Which word does not belong in the following list:
Which word does not belong in the following list: Stop cop mop chop prop shop or crop?Read More »No voice, but it still cries riddle
No voice, but it still cries. No wings, but it still flutters. No teeth, but it still bites. No mouth, ...Read More »Can you find the killer?
Sherlock holmes is called upon on a crime scene. A woman has been killed and there are only three suspects ...Read More »I am under you, above you, all around you puzzle
When I’m under you, I’m a five letter word. Take out the first letter and I come above you. Take ...Read More »Keep you Safe & Fine
It makes you weak at the worst of all times. It keeps you safe and fine. It makes your hands ...Read More »How far CARDIFF city from you
Distances from you to certain cities are given below. BERLIN 200 km PARIS 300 km ROME 400 km AMSTERDAM 300 ...Read More »Runs but never flee
It runs but can never flee. It is often watched, yet never sees. When long it brings boredom, When short ...Read More »Chairs around a table
How many chairs would you need around a table to sit for four Sons, four fathers, and two grandfathers ?Read More »Weak defeat the strong and then defeat themselves riddle
How can the weak defeat the strong, but at a later date, defeat themselves. How is it possible?Read More »3 Question and 1 answer Riddle
One Mother and Daughter went to a market. .. The Shopkeeper asked the girl 3 questions. .. 1. WHAT DID ...Read More »Relationship Riddle
A conversation between 2 people: A – “Hello. Is this XYZ?” B – “Yes. May I know who is this?” ...Read More »Name The Monkey
Mrs. Robinson’s 4th grade class took a field trip to the local zoo. The day was sunny and warm – ...Read More »Great Banquet
A great banquet was prepared for a Roman emperor and his courtiers. 22 Dormice, 40 Larks’ Tongues, 30 Flamingos and ...Read More »Missing digit riddle
John recently moved to his first brand new house. When he arrived there he discovered that the builder had forgotten ...Read More »How many remain?
You have a cube made of 10 x 10 x 10 smaller cubes, for a total of 1000 smaller cubes. ...Read More »