# Tic-Tac-Toe Puzzle to place numbers

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You have to place all the digits from 1 to 9 without repeating any number in a tic tac toe board..
So, that the numbers should add up to 15 whether you add the numbers in each row, column or diagonally.

SherlockHolmes Expert Asked on 29th October 2015 in

i Have found out elements using C program. Ans is

4 | 9 | 2
———-
3 | 5 | 7
———-
8 | 1 | 6
Here is the code.

``````#include < stdio.h >
#include < conio.h >
int main() {
int size = 3;
int matrix[3][3]; // = {{4,9,2},{3,5,7},{8,1,6}};
int row, column = 0;
int sum, sum1, sum2;
int flag = 0;
printf("nEnter matrix : ");
for (row = 0; row < size; row++) {
for (column = 0; column < size; column++)
scanf("%d", & matrix[row][column]);
}

printf("Entered matrix is : n");
for (row = 0; row < size; row++) {
printf("n");
for (column = 0; column < size; column++) {
printf("t%d", matrix[row][column]);
}
}

//For diagonal elements
sum = 0;
for (row = 0; row < size; row++) {
for (column = 0; column < size; column++) {
if (row == column)
sum = sum + matrix[row][column];
}
}

//For Rows
for (row = 0; row < size; row++) {
sum1 = 0;
for (column = 0; column < size; column++) {
sum1 = sum1 + matrix[row][column];
}
if (sum == sum1)
flag = 1;
else {
flag = 0;
break;
}
}

//For Columns
for (row = 0; row < size; row++) {
sum2 = 0;
for (column = 0; column < size; column++) {
sum2 = sum2 + matrix[column][row];
}
if (sum == sum2)
flag = 1;
else {
flag = 0;
break;
}
}

if (flag == 1)
printf("nMagic square");
else
printf("nNo Magic square");
return 0;
}
``````

ketul Expert Answered on 29th October 2015.

Superb (Y)

on 29th October 2015.

code is not even compiling !

on 16th April 2016.

6 7 2
1 5 9
8 3 4

g Curious Answered on 5th November 2015.

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