Cost of bat = $49.5
Cost of ball = $0.5

EXPLANATION–
Bat is $49 more than ball

let ball costs $x
So, Bat costs $49+$x

Total cost = $50

$x+$49+$x=$50
$x=$0.5

So, Cost of bat = $49.5
Cost of ball = $0.5

Answer – Assassination

Standing Positions-
1. Ass
2. Ass
3. I
4. Nation

Ass ass i nation

So its, Assassination

Tom (T+o+m) = 48

Dick (D+i+c+k) = 27

harry(h+a+r+r+y) = 70

Explanation:
if we assign weights to our alphabets as per their position.
A/a–>1
B/b–>2
C/c–>3
D/d–>4
E/e–>5
F/f–>6
G/g–>7
H/h–>8
I/i–>9
J/j–>10
K/k–>11
L/l–>12
M/m–>13
N/n–>14
O/o–>15
P/p–>16
Q/q–>17
R/r–>18
S/s–>19
T/t–>20
U/u–>21
V/v–>22
W/w–>23
X/x–>24
Y/y–>25
Z/z–>26
Then,
Tom=T+o+m=20+15+13=48
Dick=D+i+c+k=4+9+3+11=27

Hence ,
Harry=H+a+r+r+y=8+1+18+18+25=70

Hence,Harry must be followed by 70

ANSWER = 13

Explaination-
Using hint 1 and 2

• Hint 1   : start and finish at \”?\”(it’s about results);

• Hint 2  : order of the operations is not important (result is between: 10 < ? < 15);

We  ca

Answer – Rs.1000 LOSS

EXPLAINATION-

Transaction 1 (Lady and Shopkeeper 1)

Lady to shopkeeper  =    Rs. 1000(FAKE)                                     = Rs 0             (EARN Rs.0)
Shopkeeper to Lady  =    Rs. 200 goods + Rs. 800 change  = Rs.1000    (EARN  –Rs.1000 ) – LOSS
Shopkeeper 2 given and took back Rs1000   –   NO NEED TO CONSIDER

FINALLY-
Shopkeeper 1 loss:     Rs.200 goods+ Rs.800 change – Rs. 1000 fake=  Rs.1000

WAAAAAAV  Its amazing, I was not believing so i deleted Rest of the part and look what i got.

NO, It is not possible.

This can be explained by information theory. We need to extract 16 units of information (A ball may be light or heavy -2 units and it can be one of 8 balls). However, we gain just 3 units of information (light, heavy or equal).

So, we need ceil[log3(16)] = 3 weighings.

In the similar question you linked to, we had 24 units of information and so we needed ceil[log3(24)] = 3 weighing.

______________________________________________
Answer Source – Simranjit Kohli, Googler

Divide the balls into the following groups: (1,2,3),(4,5,6),(7,8)

Step 1.
Weigh (1,2,3) against (4,5,6)

Two possible outcomes:
The two groups are equally heavy. (Case A)
One of these groups is heavier than the other. (Case B)

Case A
Weigh 7 against 8.  Now you have identified the heavier ball in 2 weighing.

Case B
Take the heavier group (assume it to be (1,2,3)), take any two balls and weigh them against each other. Either one of these is heavier else the third ball is.

There are a number  of solutions –

Solution 1-