One option is:
strike, one, strike , one , strike, strike, one, strike, one, strike, strike , strike
11 +   1     +11    +   1  +    21       +11    + 1     + 11   + 1  + 30 = 99

Well, as Isaac Asimov once wrote:  There is not enough data for a meaningful answer!!.
I suppose you mean after they gave him the children’s answer (because he could not no in advance know that this will be the situation).
If we choose  to mark the  #of girls as “G” and the number of boys as “B” then we have G+B =612
Since there are a lot combinations where 0.5G+0.75B = integer number, than the highest number of  oranges will be 3055 (in case of 608 girls and 4 boys), but if we assume than they are almost the same number than in case of 308 girls and 304 boys  he had to buy 2680 oranges and if vise versa 2675

Let the age of the boiler now be B, and the age of the ship now be S. According to the problem statement, we have the following two equations:

• S = B + (B/2) = (3/2)B (the age of the ship when the boiler was as old as it is now was B/2, and the ship was twice as old as the boiler at that time)
• S + B = 30 (the sum of the ages of the ship and the boiler is 30)

We can substitute the first equation into the second equation to get:

(3/2)B + B = 30

Solving for B, we get:

B = 12

Substituting B = 12 into the first equation, we get:

S = (3/2)B = 18

Therefore, the age of the boiler is 12 years and the age of the ship is 18 years.

In order for them to start on the right foot they need to make an even number of steps So the number of steps the short man takes will always be a multiple of 3, while the number of steps the tall man takes will always be a multiple of 2. Therefore, if they start on the left foot, they will never step out together on the right foot because the number of steps they take will never have a common multiple of 2 and 3. or in other words the short man can not make a 3/2 step so they will never step out with right feet together

1) Depends on the amount of people in the group and the knowledge of the bettor about the people in my social group.
2) The problem of finding the minimum size of a group to have a probability of at least 50% of finding two people with the same birthday is a classic problem in probability known as the birthday problem or the birthday paradox.To solve the problem, we need to calculate the probability of two people not having the same birthday in a group of n people, and then set this probability to be less than 50%. The probability of two people not having the same birthday in a group of n people can be calculated as follows:

P(n) = (365/365) * (364/365) * (363/365) * … * ((365 – n + 1)/365)

where (365/365) is the probability that the first person has a unique birthday, (364/365) is the probability that the second person has a different birthday than the first person, and so on, until ((365 – n + 1)/365) is the probability that the nth person has a different birthday than the first n – 1 people.

To find the smallest value of n for which P(n) is less than 0.5, we can use trial and error, or we can use a formula derived from the above expression, known as the approximate formula:

n ≈ √(2 * 365 * ln(1/(1 – 0.5)))

Using this formula, we can calculate that the minimum size of a group to have a probability of at least 50% of finding two people with the same birthday is approximately 23. This means that in a group of 23 people, there is a 50-50 chance that at least two of them share the same birthday.

Based on the information provided, we can determine the owners of each car:

• Alan owns the silver Mercedes.
• Mr Smith owns the blue Ferrari.
• Mr Richards owns the red Rolls Royce.
• Charles owns the green Corvette.

Now since Alan has a Mercedes his last name can not be Smith or Richards and since we know that Mr Stone was “listened intently” to Charles than Charles can not be Mr Stone so the only option left is that Alrn is Mr Stone and therefor Charles is Mr Wilshaw. And Since Mr Smith “went to great lengths to explain to Brian” than Mr Smith can not be Brian so he has to be David and Brian is Mr Richards.

so the solution is
Alan Stone  owns the silver Mercedes.
David Smith owns the blue Ferrari.
Brian Richards owns the red Rolls Royce.
Charles Wilshaw owns the green Corvette.

They can all be rearrange to form a new word:
1) charm > march
2) dynamo > Monday
3)  yam – may
4) reay > year
5) ear – are
6) one > eon
7) toady > today

1. The rearranged letters form the word “ruralier”.
2. The rearranged letters form the word “traveler”.
3. The rearranged letters form the word “pronoun”.

The answer to this riddle is simply: “A pair of eyes”.

The first eye, located in a blue face, sees another eye located in a green face. The first eye remarks that the second eye is “like to this eye”, meaning that they are similar or alike in some way. However, the first eye also notes that the second eye is “in low place not in high place”, suggesting that the second eye is located lower on the face than the first eye.

Taken together, the clues indicate that the answer to the riddle is a pair of eyes, which are similar to each other but are located at different heights on a face, with one eye typically being located higher than the other.