5196751830

6 x (6 – 3) = 18
18 x (18 – 3) = 270
270 x (270 – 3) = 72090
72090 x (72090 – 3) =  5196751830

Arrange them in a star-like configuration, with tips touching each other.

The question asks to “move” one matchstick. ‘Move’ doesn’t necessarily mean that it should be moved to anywhere within the given equation / statement. Hence:

Remove the middle stick of the ‘8’ to make it ‘0’, making the statement 6 – 6 = 0, which is true. Otherwise – if the stick must be placed within the statement – move the lower left stick of ‘8’ (to make it ‘9’) and place it over the ‘=’ symbol, making it an inequality, which is also true.

Ball (is) in your court

Ball, in any ball game that involve ‘service’ (such as tennis) OR shuttle cock in shuttle badminton.

One possible solution:

House 1: Blue, owned by Jennifer
House 2: Red, owned by Sharon
House 3: White, owned by Cruz
House 4: Green, owned by Danny

Move the sticks as indicated by the arrows in the image below. i.e., move the horizontal stick half-way to the right and move the left stick over to the right end of the horizontal stick, shifting down, to be in parallel with the lower vertical stick. With this, the ‘wine glass’ figure will be turned upside down and the fly will be outside. 

(In the image, the dashed lines indicate original position of the sticks.)

Image 5 rotated 90 degrees clockwise becomes image 6.

Move the bottom left coin and bottom right coin to the left and right of the second row (having two coins).

With this:

1. 1. The second row will have four coins;

1. 1. The third row will remain unchanged (3 coins)

1. 1. Fourth row will have two coins

i.e., the state of second and fourth rows get interchanged.

Now move the single coin from the top to below the current fourth row (which now has 2 coins only). With this, the second row (which now has four coins) becomes the top row, the second row remains with three coins, whereas the third row has two coins and the single coin which was moved from the top now forms the fourth row having a single coin, thereby inverting the triangle.

In the image, follow the arrows:

Move the coin G to the left of coin B and move coin J to the right of coin C, and move coin A to the bottom, below and between the coins H and I. The final arrangement will be coins GBCJ on top row, DEF on second row (unchanged), H and I on third row and coin A alone on the bottom.

Let H: Horse; S: Horseshoe; B: Boot

1. H + H + H = 3H = 30 => H = 10
2. H + 2S + 2S = 18 => 10 + 4S = 18 => S = 2
3. 2S – 2B = 2 => 4 – 2B = 2 => B = 1

4. B + H x S = 1 + 10 X 2 = 21