Cash a car riddle
A man is going to an Antique Car auction. All purchases must be paid for in cash. He goes to the bank and draws out $25,000.
Since the man does not want to be seen carrying that much money, he places it in 15 envelopes numbered 1 through 15, in such a way that he can pay any amount up to $25,000 without having to open any envelope. Each envelope contains the least number of bills possible of any available US currency (for example, no two tens instead of a twenty).
At the auction, he makes a successful bid of $8322 for a car. He hands the auctioneer envelopes 2, 8, and 14. After opening the envelopes, the auctioneer finds exactly the right amount.
The question: How many ones did the auctioneer find in the envelopes?
1 one will be found only
envelopes will have 1 ,2,4,8,16,,32,64,128,256,512,1024,2048,4096,8192,16384
2 .8 ,14 envelope will have 2,128,8192 dollars respectively and 128 dollars will have one 1 among them
What I am missing in the question is what bills are available in the US currency.
Of course I can look it up but it should be mentioned in the question.
Obviously the bills are not the same as for the Euro currency, because the Euro doesn’t have any 1 Euro bills only coins.
Your Answer
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