Cash a car riddle

A man is going to an Antique Car auction. All purchases must be paid for in cash. He goes to the bank and draws out $25,000.

Since the man does not want to be seen carrying that much money, he places it in 15 envelopes numbered 1 through 15, in such a way that he can pay any amount up to $25,000 without having to open any envelope. Each envelope contains the least number of bills possible of any available US currency (for example, no two tens instead of a twenty).

At the auction, he makes a successful bid of $8322 for a car. He hands the auctioneer envelopes 2, 8, and 14. After opening the envelopes, the auctioneer finds exactly the right amount.

The question: How many ones did the auctioneer find in the envelopes?

Share
SherlockHolmes Expert Asked on 7th October 2018 in Logic Puzzles.
Add Comment

  • 2 Answer(s)

    1 one will be found only
    envelopes will have 1 ,2,4,8,16,,32,64,128,256,512,1024,2048,4096,8192,16384
    2 .8 ,14 envelope will have 2,128,8192 dollars respectively and 128 dollars will have one 1 among them

    Yodha Expert Answered on 7th October 2018.
    Add Comment

    What I am missing in the question is what bills are available in the US currency.
    Of course I can look it up but it should be mentioned in the question.
    Obviously the bills are not the same as for the Euro currency, because the Euro doesn’t have any 1 Euro bills only coins.

    CugelTheWise Genius Answered on 8th October 2018.
    Add Comment
  • Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.
  • More puzzles to try-

  • Tags