the letter t is before u

1

the words “your exact weight” were written by you

MIC CROW SOFTY  so answer should be microsoft

passage

1 then 2 then 3 then 4 then 5 etc (how  moves go)
so position  of apple will be like,1,1+2,1+2+3,1+2+3+4,as every move goes (position from first plate)
so if we divide total by number of plates remainder will tell the position of apple at end .since sum  can be formalised into n(n+1)/2 where n is last value  of series .so the number of plates must be factor of n(n+1)/2 if we want it to end in first place.
so if number of plates is k then if i choose n=k square.(k^2)  so it will be.k^2(k^2 +1)/2 should be divisible by k and  it is divisible by k so it will always happen no matter how many plates it is always possible

Answer –  44 Steps

5 steps forward 3 steps backward
2m 8 steps
similarly,
4 m 16 steps
6m 24 steps
8m 32 steps
10m 40 steps.
now in 4 steps he will fall in hole.
Hole is after 13 m not at 13 m .

61

q can be 1 to 9
if q is 2,4,5,8, mult mn is zero as in those cases some of A,B,C,D,E,F, WILL BE ZERO.
IF Q IS 7 P IS LESS THEN 7 AND ANY NUMBER MULTIPLIED BY  142857 (1/7=0.142857) LESS THEN 7 HAVE SAME DIGITS.SO MULTI MIN FOR ALL 1/7 TO 6/7 WILL BE SAME (CYCLIC NUMBER).IF Q IS 9 THEN IT IS ALL ABOUT SIXTH ROOT AS 2/9 =0.222222…..
SIMILARLY FOR OTHERS.
IF Q IS 3  THEN IT  CAN BE REPRESENTED IN 9 CASE AS 2/3=6/9     1/3=3/9
IF Q IS 6 THEN 2/6 IS SAME AS 1/3,          4,6 AS 2/3         3/6 AS 1/2 ONLY 5/6 IS .833333
SO THE MULTIMINN NABILA REFEREED WAS 8 *3*3*3*3*3 AS IT IS THE ONLY ONE BY WHICH WE CAN DIRECTLY IDENTIFY THE NUMBER

EDIT
I FORGOT ABOUT 1/6 AND 1/9 IF MULTIMIN IS 1 THEN NUMBER WILL BE 1/9
AND  IF IT IS 6^5 THEN IT IS 1/6 AS IT IS 0.166666
SO SHE WILL  SEE  IF  MULTIMINN IS NOT SIXTH POWER OR FIFTH POWER OF A DIGIT THEN NUMBER WILL BE  5/6
OTHERWISE THOSE UNIQUE CASES ARE PREVIOUSLY MENTIONED

she have already calculated all of them before and they were distinct .obviously it was about her numbers whom she play with so she would have known them.