1299
points
Questions
36
Answers
150

Arrange the figures in the following way:
and both sums add up alike.
173 85
+ 4 + 92
177 177 4256 views
 1 answers
 0 votes

Weary Willie must have worked 1673 days and idled l3Y.! days. Thus the former time, at $8.00 a day, amounts to exactly the same as the latter at $10.00
 5542 views
 2 answers
 0 votes

The amount must have been $31.63. He received $63.31. After he had spent a nickel there would remain the sum of $63.26, which is twice the
amount of the check. 4134 views
 1 answers
 0 votes

Make 2 piles with equal number of coins. Now, flip all the coins in one of the pile.
How this will work? lets take an example.
So initially there are 5 heads, so suppose you divide it in 2 piles.
Case:
P1 : H H T T T
P2 : H H H T TNow when P1 will be flipped
P1 : T T H H HP1(Heads) = P2(Heads)
Another case:
P1 : H T T T T
P2 : H H H H TNow when P1 will be flipped
P1 : H H H H TP1(Heads) = P2(Heads
 8321 views
 1 answers
 0 votes

Now let’s look at some sample paths we can figure out by inspection.
If we start at A and move towards B, we find we can follow the path
RRRUU
(where R = Right one unit, U = Up one unit),
UURRR,
RURUR,
RRUUR,and so on.
By analyzing our good routes, we see that every good route consists of 5 moves and we have 3 R moves and 2 U moves. We canuse this to generalize a formula to find the number of possible routes.
Since as we’ve shown, order does not matter in our paths (we can have an R in any place of our 5 moves), we can use our combination formula:
C(N,R) = N!/(NR)! * R!
The number of how many good routes we have can be found by finding how many combinations of 3 R’s we can have in our 5 moves, so we want to calculate:
C(5,3) = 5!/(53)! * 2! = 10
 5255 views
 1 answers
 0 votes

If X is the temperature9X/5 = X — 32
Therefore X=40C = 40 F 5277 views
 1 answers
 0 votes

The entire mile was run in nine minutes. Though fr.>m the facts given we cannot determine the time taken over the first and second quartermiles separately, we know, however, that together they took four and a half minutes. And the last two quarters were run in two and a quarter minutes each.
 4482 views
 1 answers
 0 votes

 4047 views
 1 answers
 0 votes

We know that there were five droves with an equal number in each drove, and therefore the number must be divisible by 5. As every one of the eight dealers bought the same number of animals, the number must also be divisible by 8. This leads us to the conclusion that the number must be a multiple of 40.
Now the highest possible multiple of 40 that will work will be found to be 120, and this number could be made up in one of two ways—1 cow, 23 sheep and 96 pigs or 3 cows, 8 sheep and 109 pigs. But the first does not fit in because the animals consisted of ‘Cows, Sheep and Pigs’ and a single ‘Cow’ is not ‘Cows’. Therefore the second possibility is the correct answer. 6383 views
 1 answers
 0 votes

The key to the solution is that with a little bit of pencil work, it will be found, while I can walk 5 miles, my friend who started from Tumkur can walk 7 miles. Let’s assume the distance between Bangalore and Tumkur is 24 miles, then the point of meeting would be 14 miles from Bangalore, and therefore I walked 3+(3/7)miles per hour while my friend walked 4 +4/5 miles per hour, and we both arrived exactly at 7 P.M
 6746 views
 2 answers
 0 votes