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# A numeric lock has a 3 digit key-

HINT-

A. 6 8 2 – One Number is correct and well placed
B. 6 1 4 – One Number is correct but wrong place
C. 2 0 6 – Two Numbers are correct but Wrong Places
D. 7 3 8 – Nothing is correct
E. 8 7 0 – One Number is correct but wrong place

SherlockHolmes Expert Asked on 29th March 2020 in

## The code is 0 4 2

Explanation-
A. 6 8 2 – One Number is correct and well placed – Number cannot be 6 as that will make Statement B wrong so the number in code is 2 which is correctly placed also(on Position 3)
B. 6 1 4 – One Number is the correct but wrong place – 6 cannot be that number as per Statement A, It cannot be 1 also as if the number is 1 it can be on either on 1st or 3rd place those are already taken by digits 0 and 2 so the only number left is 4
C. 2 0 6 – Two Numbers are correct but Wrong Places – One of digit which is correct is 0 as per Statement E but its place cannot be at second(as per statement C) and third position( as per Statement E) so it can be only one first place, another digit is 2 as per statement A.
D. 7 3 8 – Nothing is correct – We can rule out these 3 digits from other statements
E. 8 7 0 – One Number is the correct but wrong place – We know 0 is one of the digit in code but the place for it would be not 3

From statements A, B and E we got our numbers.
Statement A gave a position for Number 2. – Statement A -> _ _ 2
Statement C and E gave a position for the other 2 numbers. Statement A, C and E-> 0 _ 2
Statement B -> last digit 4 which will come in the middle so code would be 0 4 2

Finally, the code is 0 4 2

SherlockHolmes Expert Answered on 29th March 2020.

The code is 102. It fits all the conditions.

Leen118 Guru Answered on 4th April 2020.

062

topijes Starter Answered on 10th April 2020.

042

codeanshul Curious Answered on 20th April 2020.

042

Mergipearl Starter Answered on 3rd May 2020.

042

Swasthiksbhat Curious Answered on 3rd August 2020.

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