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There are 100 coins placed on a table in a dark room, out of which 20 coins are showing tails and 80 coins are showing heads. The task is to divide this set of 100 coins into 2 groups (not necessarily same size) such that both groups have the same number of coins showing the tails.

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SherlockHolmes Expert Asked on 9th August 2020 in Logic Puzzles.
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  • 1 Answer(s)

    Divide the 100 coins into 2 groups
    Group1 with 20 coins

    Group2 with 80 coins.

    Assume that Group2 has 15 coins are showing tails,
    Hence in Group1, 5 coins will show tails, 15 coins will show heads (there are total 20 coins showing tails)

    Flip all the coins in Group1 – so now, 15 coins will be showing tails which is the same number as in Group2.

    bhola99 Expert Answered on 9th August 2020.
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