Find the ages and number of nuts
Last time I visited a friend’s farm near Bangalore he gave me a bag containing 1000 peanuts. From this I took out 230 peanuts for use in my own home and gave away the bag with the remainder of peanuts to three little brothers who live in my neighbourhood and told them to distribute the nuts between themselves in proportion to their ages which together amounted to 17.5 years.
Tinku, Rinku and Jojo, the three brothers, divided the nuts in the following manner:
As often as Tinku took four Rinku took three and as often as Tinku took six Jojo took seven.
With this data can you find out what were the respective ages of the boys and how many nuts each got?
When Tinku takes 12, Rinku and Jojo will take 9 and 14 respectively—and then they would have taken altogether thirty-five nuts.
Thirty-five is contained in 770 twenty-two times which means all one has to do now is merely multiply 12, 9 and 14 by 22 to find that Tinku’s share was 264, Rinku’s 198 and Jojo’s 308. Now as the total of their ages is 17.5 years or half the sum of 12, 9 and 14, their respective ages must be 6, 4.5 and 7 years.
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