# Horse Race Puzzle

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There are 25 horses among which you need to find out the fastest 3 horses. You can conduct race among at most 5 horses in a single race to find out their relative speed. At no point you can find out the actual speed of the horse in a race. Find out minimum number of races are required to find the 3 horses.

anikam Expert Asked on 22nd August 2015 in

The answer is 7 .Here’s how :
Divide the horses into group of 5 (A,B,C,D,E) and conduct 5 races to find 5 fastest horses .
Now conduct a race among these to find the fastest horse (Let’s say it’s from group E) .and let’s also assume that fastest horse from group D came 2nd and C came 3rd. Total 6 races done. Now the second fastest horse can be the one who came second in the group E which gave us the fastest horse or the one which came second in 6th race. Similarly the 3rd fastest horse can be
the either fastest horse from group D and C ,or the horses which came 2nd and 3rd in group E or the horse which came second in group D. Conduct a race among these 5 horses and you will get the result in final and 7th race.

pnikam Expert Answered on 22nd August 2015.

My answer is 11.

First you split the 25 horses into 5 groups of 5. The puzzle tells us that we can’t measure speed, only relative speed, so we can’t compare horses across races. Thus, we have to take the top 3 horses of each race.  (5 races)

Next, we have 15 horses so we split them into 3 groups of 5. We again take the top 3 of each group.  (3 races)
Then, from the remaining 9, we form one group of 5 and take the top 3, adding it to the remaining 4. (1 race)
Now we have 7 remaining, we form another group of 5 and take the top 3, adding it to the remaining 2. (1 race)
We now have 5 horses left and we can form our top 3 in this final race. (1 race)

Add them up and you’ve got 11 races.

yonesbones Starter Answered on 2nd February 2017.

The reason I disagree with the first answer:

Imagine a scenario where 3 horses of race #2 are faster than the fastest horse of race #1. You’ve eliminated the 2nd and 3rd fastest horses.

on 2nd February 2017.

You have to assume the horses will not tire, which is not realistic. Any way, you would race horse # 1 with horse # 2 and the winner would race horse #3. The winner of that race then races horse #4. And so on down the line until horse # 25 races. Minimum # of races is 26.

ghostpine Starter Answered on 3rd February 2017.

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