shortest path riddle
A 12 by 25 by 36 inch box is lying on the floor on one of its 25 by 36 inch faces. An ant, located at one of the bottom corners of the box, must crawl along the outside of the box to reach the opposite bottom corner. It can walk on any of the box faces except for the bottom face, which is in flush contact with the floor. What is the length of the shortest such path?
One obvious route is for the ant to crawl along the line of contact between the box and the floor.
This is clearly 25 + 36 = 61 cm in length.
Can the ant find a shorter path by crawling over the top of the box?
The key insight is to flatten the box. Having done this, it’s clear that the shortest path must be one of the straight line paths from one corner to its opposite. There are four such paths. They are the diagonals of:

 a 36 by 12+25+12 cm rectangle

 a 25 by 12+36+12 cm rectangle

 two 12+25 by 12+36 cm rectangles
Using Pythagoras’ Theorem, the lengths of these diagonals are, respectively, the square roots of 3697, 4225, and 3673. Note that 61^{2} = 3721, and so the path along the line of contact between the box and the floor is longer than all but one of these diagonals.
The shortest path over the box is therefore cm, or a little over 60.6 cm.
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